Pytorch RNN 用sin預測cos
RNN簡單介紹
什么是RNN
RNN的全稱是Recurrent Neural Network,中文名稱是循環(huán)神經(jīng)網(wǎng)絡。它的一大特點就是擁有記憶性,并且參數(shù)共享,所以它很適合用來處理序列數(shù)據(jù),比如說機器翻譯、語言模型、語音識別等等。
它的結構

它的更新公式
(Pytorh 文檔里的 https://pytorch.org/docs/stable/generated/torch.nn.RNN.html?highlight=rnn#torch.nn.RNN)

sin to cos
我們這里采用的是一個seq2seq的模型,也就是,首先生成區(qū)間(a,b)的等距采樣點steps=[s0,s1,s2,...sn],然后再算出x = [x0,x1,x2,...xn], xn = sin(sn),和y = [y0, y1,y2,...,yn], yn = cos(sn)。
RNN要做的是,把序列x轉變成序列y,也即是從sin到cos(下圖中藍色到紅色)

可以知道,y0只受到x0的影響,而y2則同時受到[x0,x0,x1,x2]的影響,同理yn則受到[x0,...xn]的影響。
代碼
import torch
from torch import nn
import numpy as np
import matplotlib.pyplot as plt
steps = np.linspace(0, np.pi*2, 100, dtype=np.float32)
input_x = np.sin(steps)
target_y = np.cos(steps)
plt.plot(steps, input_x, 'b-', label='input:sin')
plt.plot(steps, target_y, 'r-', label='target:cos')
plt.legend(loc='best')
plt.show()
class RNN(nn.Module):
def __init__(self, input_size, hidden_size):
super(RNN, self).__init__()
self.hidden_size = hidden_size
self.rnn = nn.RNN(
input_size = input_size,
hidden_size = hidden_size,
batch_first = True,
)
self.out = nn.Linear(hidden_size, 1)
def forward(self, input, hidden):
output, hidden = self.rnn(input, hidden)
output = self.out(output)
return output,hidden
def initHidden(self):
hidden = torch.randn(1, self.hidden_size)
return hidden
rnn = RNN(input_size = 1, hidden_size = 20)
hidden = rnn.initHidden()
optimizer = torch.optim.Adam(rnn.parameters(), lr=0.001)
loss_func = nn.MSELoss()
plt.figure(1, figsize=(12, 5))
plt.ion() # 開啟交互模式
loss_list = []
for step in range(800):
start, end = step * np.pi, (step + 1) * np.pi
steps = np.linspace(start, end, 100, dtype=np.float32)
x_np = np.sin(steps)
y_np = np.cos(steps)
#(100, 1) 不加batch_size
x = torch.from_numpy(x_np).unsqueeze(-1)
y = torch.from_numpy(y_np).unsqueeze(-1)
y_predict, hidden = rnn(x, hidden)
hidden = hidden.data # 重新包裝數(shù)據(jù),斷掉連接,不然會報錯
loss = loss_func(y_predict, y)
optimizer.zero_grad() # 梯度清零
loss.backward() # 反向傳播
optimizer.step() # 梯度下降
loss_list.append(loss.item())
if step % 10 == 0 or step % 10 == 1:
plt.plot(steps, y_np.flatten(), 'r-')
plt.plot(steps, y_predict.data.numpy().flatten(), 'b-')
plt.draw();
plt.pause(0.05)
plt.ioff()
plt.show()
plt.plot(loss_list)
效果






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