【題目】
1. 下圖為三層神經(jīng)網(wǎng)絡(luò)結(jié)構(gòu),表中為輸入的4條樣本數(shù)據(jù),計算第2個訓(xùn)練樣本的前向傳播過程,網(wǎng)絡(luò)參數(shù)的初始為:<span id="MathJax-Span-2" class="mrow"><span id="MathJax-Span-3" class="msubsup"><span id="MathJax-Span-4" class="mi">W<span id="MathJax-Span-5" class="mn">1W1=[[0.1,0.2],[0.2,0.3]],theta1=[0.3,0.3],<span id="MathJax-Span-7" class="mrow"><span id="MathJax-Span-8" class="msubsup"><span id="MathJax-Span-9" class="mi">W<span id="MathJax-Span-10" class="mn">2W2=[[0.4,0.5],[0.4,0.5]],theta2=[0.6,0.6]。


1. 根據(jù)上題中的神經(jīng)網(wǎng)絡(luò)結(jié)構(gòu)和參數(shù)、數(shù)據(jù),請計算反向傳播過程中<span id="MathJax-Span-12" class="mrow"><span id="MathJax-Span-13" class="msubsup"><span id="MathJax-Span-14" class="mi">W<span id="MathJax-Span-15" class="texatom"><span id="MathJax-Span-16" class="mrow"><span id="MathJax-Span-17" class="mo">(<span id="MathJax-Span-18" class="mn">1<span id="MathJax-Span-19" class="mo">,<span id="MathJax-Span-20" class="mn">2<span id="MathJax-Span-21" class="mo">)<span id="MathJax-Span-22" class="mn">1W1(1,2)的更新過程。
【要求】
1.激活函數(shù)使用sigmoid函數(shù),損失函數(shù)使用均方差函數(shù);
2.請大家在博客中直接完成或在作業(yè)本上完成后拍照上傳。

浙公網(wǎng)安備 33010602011771號