#include<iostream>

using namespace std;
int n;
int a[10] = {6,2,5,5,4,5,6,3,7,6};  
int cnt;

int match(int num){
	int k = 0;//每個數字的火柴棍數量
	for(int i = num;i!=0;i/=10) k+=a[i%10];
	if(num == 0) k += a[0];
	return k;
}

int main(){
	cin >> n;
	int res = 0;
	for(int i = 0;i <= 1000;i++)
		for(int j = 0;j <= 1000;j++){
			if(match(i) + match(j)  + match(i+j) == n - 4)
				res ++;
		}
		cout << res << endl;

	return 0;
}