#include <vector>
#include <map>
#include <iostream>
#include <math.h>
/**
*
給定兩個非空鏈表來表示兩個非負整數。位數按照逆序方式存儲，它們的每個節點只存儲單個數字。將兩數相加返回一個新的鏈表。

你可以假設除了數字 0 之外，這兩個數字都不會以零開頭。

示例：

輸入：(2 -> 4 -> 3) + (5 -> 6 -> 4)
輸出：7 -> 0 -> 8
原因：342 + 465 = 807
*/
using namespace std;

struct ListNode{
    int val;
    ListNode *next;
    ListNode(int x) : val(x), next(NULL){}
};

template<class T>
int length(T& arr) {
    return sizeof(arr)/ sizeof(arr[0]);
}

class Solution {
public:
    ListNode* addTwoNumbers(ListNode* l1, ListNode* l2) {
        uint64_t carry = 0, sum = 0;
        ListNode prehead(0), *p = &prehead;

        while (l1 || l2) {
            sum =  (l1 ? l1->val : 0) + (l2 ? l2->val : 0) + carry;
            sum = carry / 10;
            p->next  = new ListNode(sum % 10);

            l1 = l1 ? l1->next : l1;
            l2 = l2 ? l2->next : l2;
            p = p->next;
        }
        return prehead.next;
    }
};

int main(int argc, char** argv){
    int a[] = {2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,9};
    ListNode* tmp = new ListNode(0);
    ListNode* ptr1 = tmp;
    for (int i = 0; i < length(a); i++) {
        ptr1->next = new ListNode(a[i]);
        ptr1 = ptr1->next;
    }
    ptr1 = tmp->next;
    delete tmp;

    tmp = new ListNode(0);
    int b[] = {5,6,4,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,2,4,3,9,9,9,9};
    ListNode* ptr2 = tmp;
    for (int j = 0; j < length(b); j ++) {
        ptr2->next = new ListNode(b[j]);
        ptr2 = ptr2->next;
    }
    ptr2 = tmp->next;
    delete tmp;

    Solution* solution = new Solution();
    solution->addTwoNumbers(ptr1, ptr2);
    delete solution;
    return 0;
}