摘要:
快排思想O(N)求第k大數(shù) int quicksort(int l,int r,int k) { int midv = a[(l+r)>>1]; int i = l,j = r; while(i <= j) { while(a[i] < midv)i++; while(a[j] > midv)j-- 閱讀全文
posted @ 2024-11-29 19:34
nannandbk
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